-
- sort by index of tuple in list
- Weather:晴,北风4-5级,最高气温28 ℃
- 2005-09-07
"""
Packages: basic_datatypes.tuples
""""""
> I have a list of tuples
> [('a','p','q'),('b','r','s'),('c','t','u'),('a','v','w'),
('b','x','y')],
> and I want to print out
>
> a : p, q, v, w
> b : r, s, x, y
> c : t, uJon,
There are lots of cute ways to do this, and I
expect to see a bunch of followup posts that will
show off arcane Python wizardry, but the simple
solution is to use a dictionary.The dictionary approach is quick, easy, and
more amenable to modification.
"""### Jon's list of tuples, shuffled
t = [ ('b','y','x'),
('a','v','w'),
('b','r','s'),
('c','u','t'),
('a','p','q'), ]### build the dict
d={}
for x in t:
if x[0] in d:
d[x[0]]+=x[1:]
else:
d[x[0]]=x[1:]### print the dict, sorting the values at the
### last possible moment.
keys = d.keys()
keys.sort()
for k in keys:
d[k].sort()
print k, ':', d[k]"""
It may not be obvious from the example above, but lists
of tuples can also just be sorted in place, e.g.t = [ ('b','x','y'), ...
t.sort()Python almost always follows the principle of least
surprise in this regard.
"""-
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